Timothy Adams Wins WSOP Event #28

Timothy Adams has won Event 28 of the World Series of Poker 2012. The event, a $2,500 NLH Four-Handed competition, saw 750 entrants. The event lasted for three days, and Timothy outlasted everyone to take away his first World Series of Poker Bracelet.

The final table saw a fast pace of play, with three eliminations in the first level. When the final five was decided, play moved to the Amazon Room’s ESPN Feature Table, where eliminations continued at a slower, but still steady pace as Greg Merson, and Anthony Gregg were sent home quite promptly.

Next eliminated was James Schaaf, who went head to head with Adams when the board read Q-2-2-Q-Q. Adams had pocket tens, just enough to edge out Schaaf’s pocket fours.

When heads-up play started, it was Adams vs Rubie. It took three levels of play for Adams to finally push Rubie out of contention. With the board reading 8-Q-10-5, Adams went all In, and Rubie decided to call. Rubie’s K-Q wasn’t enough to beat Adam’s A-Q which was bolstered by an Ace on the River.

Adams walked away with not just a well deserved bracelet, but a prize of $392,476. Rubie took away $242,458, and Schaaf $164,823.

Keep checking back for more WSOP updates over the next few days.

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